2(x+6)(x-4)=2x^2+4x-48

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Solution for 2(x+6)(x-4)=2x^2+4x-48 equation: 



2(x+6)(x-4)=2x^2+4x-48

We move all terms to the left:

2(x+6)(x-4)-(2x^2+4x-48)=0

We get rid of parentheses

-2x^2+2(x+6)(x-4)-4x+48=0

We multiply parentheses ..

-2x^2+2(+x^2-4x+6x-24)-4x+48=0

We multiply parentheses

-2x^2+2x^2-8x+12x-4x-48+48=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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